type: type IdNode { idval: string idtype: string ts: int conn: [IdNode] } idval: string @index(exact) . data: { set { _:uuid1 <idval> "uuid1" . _:uuid1 <idval> "uuid" . _:uuid1 <dgraph.type> "IdNode" . _:uuid1 <ts> "12313223211" . _:uuid1 <conn> _:gm1 . _:gm1 <idval> "my…

To “Flat” things we use normalize. But, for your case, this would messup with everything. There’s no function in Dgraph that returns a flat line of objects. What you can do is use variables and multiple blocks to have the same result. e.g: PS. “idval” is a list. So it will be always like "idval":…

Return all the nodes a graph as a list using the golang client

Users Dgraph

DeepakSahoo (Deepak Sahoo) June 8, 2020, 6:03pm 3

but there can be many graphs in the system. I want to extract all the nodes of a particular graph.

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Return all the nodes a graph as a list using the golang client

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